Factor 16q^2-25

$16 q^{2} - 25$

Step 1

Rewrite $16 q^{2}$ as ${(4 q)}^{2}$ .

${(4 q)}^{2} - 25$

Step 2

Rewrite $25$ as $5^{2}$ .

${(4 q)}^{2} - 5^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 4 q$ and $b = 5$ .

$(4 q + 5) (4 q - 5)$