Factor 16x^2-121

$16 x^{2} - 121$

Step 1

Rewrite $16 x^{2}$ as ${(4 x)}^{2}$ .

${(4 x)}^{2} - 121$

Step 2

Rewrite $121$ as $11^{2}$ .

${(4 x)}^{2} - 11^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 4 x$ and $b = 11$ .

$(4 x + 11) (4 x - 11)$

Factor 16x^2-121

Related Questions

Support LCMGCF.com by disabling your adblocker.