Factor 16x^4-y^2

$16 x^{4} - y^{2}$

Step 1

Rewrite $16 x^{4}$ as ${(4 x^{2})}^{2}$ .

${(4 x^{2})}^{2} - y^{2}$

Step 2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 4 x^{2}$ and $b = y$ .

$(4 x^{2} + y) (4 x^{2} - y)$

Factor 16x^4-y^2

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