Factor (2-n)(n^2+6n)(3n-11)

$(2 - n) (n^{2} + 6 n) (3 n - 11)$

Step 1

Factor $n$ out of $n^{2} + 6 n$ .

Factor $n$ out of $n^{2}$ .

$(2 - n) (n \cdot n + 6 n) (3 n - 11)$

Factor $n$ out of $6 n$ .

$(2 - n) (n \cdot n + n \cdot 6) (3 n - 11)$

Factor $n$ out of $n \cdot n + n \cdot 6$ .

$(2 - n) (n (n + 6)) (3 n - 11)$

$(2 - n) (n (n + 6)) (3 n - 11)$

Step 2

Remove unnecessary parentheses.

$(2 - n) n (n + 6) (3 n - 11)$

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