Factor 25e^2-16

$25 e^{2} - 16$

Rewrite $25 e^{2}$ as ${(5 e)}^{2}$ .

${(5 e)}^{2} - 16$

Rewrite $16$ as $4^{2}$ .

${(5 e)}^{2} - 4^{2}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 5 e$ and $b = 4$ .

$(5 e + 4) (5 e - 4)$