Factor 27-t^3

$27 - t^{3}$

Step 1

Rewrite $27$ as $3^{3}$ .

$3^{3} - t^{3}$

Step 2

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = 3$ and $b = t$ .

$(3 - t) (3^{2} + 3 t + t^{2})$

Step 3

Raise $3$ to the power of $2$ .

$(3 - t) (9 + 3 t + t^{2})$

Factor 27-t^3

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