Factor 2m^3+54

$2 m^{3} + 54$

Step 1

Factor $2$ out of $2 m^{3} + 54$ .

Factor $2$ out of $2 m^{3}$ .

$2 (m^{3}) + 54$

Factor $2$ out of $54$ .

$2 m^{3} + 2 \cdot 27$

Factor $2$ out of $2 m^{3} + 2 \cdot 27$ .

$2 (m^{3} + 27)$

Step 2

Rewrite $27$ as $3^{3}$ .

$2 (m^{3} + 3^{3})$

Step 3

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = m$ and $b = 3$ .

$2 ((m + 3) (m^{2} - m \cdot 3 + 3^{2}))$

Step 4

Factor.

Simplify.

Multiply $3$ by $- 1$ .

$2 ((m + 3) (m^{2} - 3 m + 3^{2}))$

Raise $3$ to the power of $2$ .

$2 ((m + 3) (m^{2} - 3 m + 9))$

Remove unnecessary parentheses.

$2 (m + 3) (m^{2} - 3 m + 9)$

Factor 2m^3+54

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