Factor 2x^2+4x-96

$2 x^{2} + 4 x - 96$

Step 1

Factor $2$ out of $2 x^{2} + 4 x - 96$ .

Factor $2$ out of $2 x^{2}$ .

$2 (x^{2}) + 4 x - 96$

Factor $2$ out of $4 x$ .

$2 (x^{2}) + 2 (2 x) - 96$

Factor $2$ out of $- 96$ .

$2 x^{2} + 2 (2 x) + 2 \cdot - 48$

Factor $2$ out of $2 x^{2} + 2 (2 x)$ .

$2 (x^{2} + 2 x) + 2 \cdot - 48$

Factor $2$ out of $2 (x^{2} + 2 x) + 2 \cdot - 48$ .

$2 (x^{2} + 2 x - 48)$

Step 2

Factor.

Factor $x^{2} + 2 x - 48$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 48$ and whose sum is $2$ .

$- 6, 8$

Write the factored form using these integers.

$2 ((x - 6) (x + 8))$

Remove unnecessary parentheses.

$2 (x - 6) (x + 8)$

Factor 2x^2+4x-96

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