Factor 36j^2-100k^6m^4

$36 j^{2} - 100 k^{6} m^{4}$

Factor $4$ out of $36 j^{2} - 100 k^{6} m^{4}$ .

Factor $4$ out of $36 j^{2}$ .

$4 (9 j^{2}) - 100 k^{6} m^{4}$

Factor $4$ out of $- 100 k^{6} m^{4}$ .

$4 (9 j^{2}) + 4 (- 25 k^{6} m^{4})$

Factor $4$ out of $4 (9 j^{2}) + 4 (- 25 k^{6} m^{4})$ .

$4 (9 j^{2} - 25 k^{6} m^{4})$

Rewrite $9 j^{2}$ as ${(3 j)}^{2}$ .

$4 ({(3 j)}^{2} - 25 k^{6} m^{4})$

Rewrite $25 k^{6} m^{4}$ as ${(5 k^{3} m^{2})}^{2}$ .

$4 ({(3 j)}^{2} - {(5 k^{3} m^{2})}^{2})$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3 j$ and $b = 5 k^{3} m^{2}$ .

$4 ((3 j + 5 k^{3} m^{2}) (3 j - (5 k^{3} m^{2})))$

Factor.

Simplify.

Multiply $5$ by $- 1$ .

$4 ((3 j + 5 k^{3} m^{2}) (3 j - 5 (k^{3} m^{2})))$

Remove parentheses.

$4 ((3 j + 5 k^{3} m^{2}) (3 j - 5 k^{3} m^{2}))$

Remove unnecessary parentheses.

$4 (3 j + 5 k^{3} m^{2}) (3 j - 5 k^{3} m^{2})$

Factor 36j^2-100k^6m^4

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