Factor 36y^2-49

$36 y^{2} - 49$

Step 1

Rewrite $36 y^{2}$ as ${(6 y)}^{2}$ .

${(6 y)}^{2} - 49$

Step 2

Rewrite $49$ as $7^{2}$ .

${(6 y)}^{2} - 7^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 6 y$ and $b = 7$ .

$(6 y + 7) (6 y - 7)$