Factor 49xy^2-16x

$49 x y^{2} - 16 x$

Step 1

Factor $x$ out of $49 x y^{2} - 16 x$ .

Factor $x$ out of $49 x y^{2}$ .

$x (49 y^{2}) - 16 x$

Factor $x$ out of $- 16 x$ .

$x (49 y^{2}) + x \cdot - 16$

Factor $x$ out of $x (49 y^{2}) + x \cdot - 16$ .

$x (49 y^{2} - 16)$

Step 2

Rewrite $49 y^{2}$ as ${(7 y)}^{2}$ .

$x ({(7 y)}^{2} - 16)$

Step 3

Rewrite $16$ as $4^{2}$ .

$x ({(7 y)}^{2} - 4^{2})$

Step 4

Factor.

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 7 y$ and $b = 4$ .

$x ((7 y + 4) (7 y - 4))$

Remove unnecessary parentheses.

$x (7 y + 4) (7 y - 4)$