Factor 49y^2-36

$49 y^{2} - 36$

Step 1

Rewrite $49 y^{2}$ as ${(7 y)}^{2}$ .

${(7 y)}^{2} - 36$

Step 2

Rewrite $36$ as $6^{2}$ .

${(7 y)}^{2} - 6^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 7 y$ and $b = 6$ .

$(7 y + 6) (7 y - 6)$