Factor 49z^2-36

$49 z^{2} - 36$

Step 1

Rewrite $49 z^{2}$ as ${(7 z)}^{2}$ .

${(7 z)}^{2} - 36$

Step 2

Rewrite $36$ as $6^{2}$ .

${(7 z)}^{2} - 6^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 7 z$ and $b = 6$ .

$(7 z + 6) (7 z - 6)$