Factor 4x^2+28x+48

$4 x^{2} + 28 x + 48$

Step 1

Factor $4$ out of $4 x^{2} + 28 x + 48$ .

Factor $4$ out of $4 x^{2}$ .

$4 (x^{2}) + 28 x + 48$

Factor $4$ out of $28 x$ .

$4 (x^{2}) + 4 (7 x) + 48$

Factor $4$ out of $48$ .

$4 x^{2} + 4 (7 x) + 4 \cdot 12$

Factor $4$ out of $4 x^{2} + 4 (7 x)$ .

$4 (x^{2} + 7 x) + 4 \cdot 12$

Factor $4$ out of $4 (x^{2} + 7 x) + 4 \cdot 12$ .

$4 (x^{2} + 7 x + 12)$

Step 2

Factor.

Factor $x^{2} + 7 x + 12$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $12$ and whose sum is $7$ .

$3, 4$

Write the factored form using these integers.

$4 ((x + 3) (x + 4))$

Remove unnecessary parentheses.

$4 (x + 3) (x + 4)$

Factor 4x^2+28x+48

Related Questions

Support LCMGCF.com by disabling your adblocker.