Factor 4x^2+40x+64

$4 x^{2} + 40 x + 64$

Step 1

Factor $4$ out of $4 x^{2} + 40 x + 64$ .

Factor $4$ out of $4 x^{2}$ .

$4 (x^{2}) + 40 x + 64$

Factor $4$ out of $40 x$ .

$4 (x^{2}) + 4 (10 x) + 64$

Factor $4$ out of $64$ .

$4 x^{2} + 4 (10 x) + 4 \cdot 16$

Factor $4$ out of $4 x^{2} + 4 (10 x)$ .

$4 (x^{2} + 10 x) + 4 \cdot 16$

Factor $4$ out of $4 (x^{2} + 10 x) + 4 \cdot 16$ .

$4 (x^{2} + 10 x + 16)$

Step 2

Factor.

Factor $x^{2} + 10 x + 16$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $16$ and whose sum is $10$ .

$2, 8$

Write the factored form using these integers.

$4 ((x + 2) (x + 8))$

Remove unnecessary parentheses.

$4 (x + 2) (x + 8)$

Factor 4x^2+40x+64

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