Factor 4x^2+4x-80

$4 x^{2} + 4 x - 80$

Step 1

Factor $4$ out of $4 x^{2} + 4 x - 80$ .

Factor $4$ out of $4 x^{2}$ .

$4 (x^{2}) + 4 x - 80$

Factor $4$ out of $4 x$ .

$4 (x^{2}) + 4 (x) - 80$

Factor $4$ out of $- 80$ .

$4 (x^{2}) + 4 x + 4 \cdot - 20$

Factor $4$ out of $4 (x^{2}) + 4 x$ .

$4 (x^{2} + x) + 4 \cdot - 20$

Factor $4$ out of $4 (x^{2} + x) + 4 \cdot - 20$ .

$4 (x^{2} + x - 20)$

Step 2

Factor.

Factor $x^{2} + x - 20$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 20$ and whose sum is $1$ .

$- 4, 5$

Write the factored form using these integers.

$4 ((x - 4) (x + 5))$

Remove unnecessary parentheses.

$4 (x - 4) (x + 5)$

Factor 4x^2+4x-80

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