Factor 4x^2+8x-32

$4 x^{2} + 8 x - 32$

Step 1

Factor $4$ out of $4 x^{2} + 8 x - 32$ .

Factor $4$ out of $4 x^{2}$ .

$4 (x^{2}) + 8 x - 32$

Factor $4$ out of $8 x$ .

$4 (x^{2}) + 4 (2 x) - 32$

Factor $4$ out of $- 32$ .

$4 x^{2} + 4 (2 x) + 4 \cdot - 8$

Factor $4$ out of $4 x^{2} + 4 (2 x)$ .

$4 (x^{2} + 2 x) + 4 \cdot - 8$

Factor $4$ out of $4 (x^{2} + 2 x) + 4 \cdot - 8$ .

$4 (x^{2} + 2 x - 8)$

Step 2

Factor.

Factor $x^{2} + 2 x - 8$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 8$ and whose sum is $2$ .

$- 2, 4$

Write the factored form using these integers.

$4 ((x - 2) (x + 4))$

Remove unnecessary parentheses.

$4 (x - 2) (x + 4)$

Factor 4x^2+8x-32

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