Factor 4x^3-36x^2+80x

$4 x^{3} - 36 x^{2} + 80 x$

Step 1

Factor $4 x$ out of $4 x^{3} - 36 x^{2} + 80 x$ .

Factor $4 x$ out of $4 x^{3}$ .

$4 x (x^{2}) - 36 x^{2} + 80 x$

Factor $4 x$ out of $- 36 x^{2}$ .

$4 x (x^{2}) + 4 x (- 9 x) + 80 x$

Factor $4 x$ out of $80 x$ .

$4 x (x^{2}) + 4 x (- 9 x) + 4 x (20)$

Factor $4 x$ out of $4 x (x^{2}) + 4 x (- 9 x)$ .

$4 x (x^{2} - 9 x) + 4 x (20)$

Factor $4 x$ out of $4 x (x^{2} - 9 x) + 4 x (20)$ .

$4 x (x^{2} - 9 x + 20)$

Step 2

Factor.

Factor $x^{2} - 9 x + 20$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $20$ and whose sum is $- 9$ .

$- 5, - 4$

Write the factored form using these integers.

$4 x ((x - 5) (x - 4))$

Remove unnecessary parentheses.

$4 x (x - 5) (x - 4)$

Factor 4x^3-36x^2+80x

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