Factor 4x^3+4

$4 x^{3} + 4$

Step 1

Factor $4$ out of $4 x^{3} + 4$ .

Factor $4$ out of $4 x^{3}$ .

$4 (x^{3}) + 4$

Factor $4$ out of $4$ .

$4 (x^{3}) + 4 (1)$

Factor $4$ out of $4 (x^{3}) + 4 (1)$ .

$4 (x^{3} + 1)$

Step 2

Rewrite $1$ as $1^{3}$ .

$4 (x^{3} + 1^{3})$

Step 3

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = x$ and $b = 1$ .

$4 ((x + 1) (x^{2} - x \cdot 1 + 1^{2}))$

Step 4

Factor.

Simplify.

Multiply $- 1$ by $1$ .

$4 ((x + 1) (x^{2} - x + 1^{2}))$

One to any power is one.

$4 ((x + 1) (x^{2} - x + 1))$

Remove unnecessary parentheses.

$4 (x + 1) (x^{2} - x + 1)$

Factor 4x^3+4

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