Factor 4x^3-64x

$4 x^{3} - 64 x$

Step 1

Factor $4 x$ out of $4 x^{3} - 64 x$ .

Factor $4 x$ out of $4 x^{3}$ .

$4 x (x^{2}) - 64 x$

Factor $4 x$ out of $- 64 x$ .

$4 x (x^{2}) + 4 x (- 16)$

Factor $4 x$ out of $4 x (x^{2}) + 4 x (- 16)$ .

$4 x (x^{2} - 16)$

Step 2

Rewrite $16$ as $4^{2}$ .

$4 x (x^{2} - 4^{2})$

Step 3

Factor.

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 4$ .

$4 x ((x + 4) (x - 4))$

Remove unnecessary parentheses.

$4 x (x + 4) (x - 4)$