Factor 4xy^2-49x

$4 x y^{2} - 49 x$

Step 1

Factor $x$ out of $4 x y^{2} - 49 x$ .

Factor $x$ out of $4 x y^{2}$ .

$x (4 y^{2}) - 49 x$

Factor $x$ out of $- 49 x$ .

$x (4 y^{2}) + x \cdot - 49$

Factor $x$ out of $x (4 y^{2}) + x \cdot - 49$ .

$x (4 y^{2} - 49)$

Step 2

Rewrite $4 y^{2}$ as ${(2 y)}^{2}$ .

$x ({(2 y)}^{2} - 49)$

Step 3

Rewrite $49$ as $7^{2}$ .

$x ({(2 y)}^{2} - 7^{2})$

Step 4

Factor.

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 2 y$ and $b = 7$ .

$x ((2 y + 7) (2 y - 7))$

Remove unnecessary parentheses.

$x (2 y + 7) (2 y - 7)$