Factor 5p^2-3+(2p^2-3p^3)

$5 p^{2} - 3 + (2 p^{2} - 3 p^{3})$

Step 1

Remove parentheses.

$5 p^{2} - 3 + 2 p^{2} - 3 p^{3}$

Step 2

Add $5 p^{2}$ and $2 p^{2}$ .

$7 p^{2} - 3 - 3 p^{3}$

Step 3

Factor $- 1$ out of $7 p^{2} - 3 - 3 p^{3}$ .

Reorder the expression.

Move $- 3$ .

$7 p^{2} - 3 p^{3} - 3$

Reorder $7 p^{2}$ and $- 3 p^{3}$ .

$- 3 p^{3} + 7 p^{2} - 3$

Factor $- 1$ out of $- 3 p^{3}$ .

$- (3 p^{3}) + 7 p^{2} - 3$

Factor $- 1$ out of $7 p^{2}$ .

$- (3 p^{3}) - (- 7 p^{2}) - 3$

Rewrite $- 3$ as $- 1 (3)$ .

$- (3 p^{3}) - (- 7 p^{2}) - 1 (3)$

Factor $- 1$ out of $- (3 p^{3}) - (- 7 p^{2})$ .

$- (3 p^{3} - 7 p^{2}) - 1 (3)$

Factor $- 1$ out of $- (3 p^{3} - 7 p^{2}) - 1 (3)$ .

$- (3 p^{3} - 7 p^{2} + 3)$