Factor 5x^2+45x+40

$5 x^{2} + 45 x + 40$

Step 1

Factor $5$ out of $5 x^{2} + 45 x + 40$ .

Factor $5$ out of $5 x^{2}$ .

$5 (x^{2}) + 45 x + 40$

Factor $5$ out of $45 x$ .

$5 (x^{2}) + 5 (9 x) + 40$

Factor $5$ out of $40$ .

$5 x^{2} + 5 (9 x) + 5 \cdot 8$

Factor $5$ out of $5 x^{2} + 5 (9 x)$ .

$5 (x^{2} + 9 x) + 5 \cdot 8$

Factor $5$ out of $5 (x^{2} + 9 x) + 5 \cdot 8$ .

$5 (x^{2} + 9 x + 8)$

Step 2

Factor.

Factor $x^{2} + 9 x + 8$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $8$ and whose sum is $9$ .

$1, 8$

Write the factored form using these integers.

$5 ((x + 1) (x + 8))$

Remove unnecessary parentheses.

$5 (x + 1) (x + 8)$

Factor 5x^2+45x+40

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