Factor 64-t^3

$64 - t^{3}$

Step 1

Rewrite $64$ as $4^{3}$ .

$4^{3} - t^{3}$

Step 2

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = 4$ and $b = t$ .

$(4 - t) (4^{2} + 4 t + t^{2})$

Step 3

Raise $4$ to the power of $2$ .

$(4 - t) (16 + 4 t + t^{2})$

Factor 64-t^3

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