Factor 6r^2-11r+4

$6 r^{2} - 11 r + 4$

Step 1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 6 \cdot 4 = 24$ and whose sum is $b = - 11$ .

Factor $- 11$ out of $- 11 r$ .

$6 r^{2} - 11 (r) + 4$

Rewrite $- 11$ as $- 3$ plus $- 8$

$6 r^{2} + (- 3 - 8) r + 4$

Apply the distributive property.

$6 r^{2} - 3 r - 8 r + 4$

Step 2

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(6 r^{2} - 3 r) - 8 r + 4$

Factor out the greatest common factor (GCF) from each group.

$3 r (2 r - 1) - 4 (2 r - 1)$

Step 3

Factor the polynomial by factoring out the greatest common factor, $2 r - 1$ .

$(2 r - 1) (3 r - 4)$

Factor 6r^2-11r+4

Related Questions

Support LCMGCF.com by disabling your adblocker.