Factor 6x^2+19x-20

$6 x^{2} + 19 x - 20$

Step 1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 6 \cdot - 20 = - 120$ and whose sum is $b = 19$ .

Factor $19$ out of $19 x$ .

$6 x^{2} + 19 (x) - 20$

Rewrite $19$ as $- 5$ plus $24$

$6 x^{2} + (- 5 + 24) x - 20$

Apply the distributive property.

$6 x^{2} - 5 x + 24 x - 20$

Step 2

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(6 x^{2} - 5 x) + 24 x - 20$

Factor out the greatest common factor (GCF) from each group.

$x (6 x - 5) + 4 (6 x - 5)$

Step 3

Factor the polynomial by factoring out the greatest common factor, $6 x - 5$ .

$(6 x - 5) (x + 4)$

Factor 6x^2+19x-20

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