Factor 7x^3-7x

$7 x^{3} - 7 x$

Step 1

Factor $7 x$ out of $7 x^{3} - 7 x$ .

Factor $7 x$ out of $7 x^{3}$ .

$7 x (x^{2}) - 7 x$

Factor $7 x$ out of $- 7 x$ .

$7 x (x^{2}) + 7 x (- 1)$

Factor $7 x$ out of $7 x (x^{2}) + 7 x (- 1)$ .

$7 x (x^{2} - 1)$

Step 2

Rewrite $1$ as $1^{2}$ .

$7 x (x^{2} - 1^{2})$

Step 3

Factor.

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 1$ .

$7 x ((x + 1) (x - 1))$

Remove unnecessary parentheses.

$7 x (x + 1) (x - 1)$