Factor 8-2x-x^2

$8 - 2 x - x^{2}$

Step 1

Factor $- 1$ out of $8 - 2 x - x^{2}$ .

Reorder the expression.

Move $8$ .

$- 2 x - x^{2} + 8$

Reorder $- 2 x$ and $- x^{2}$ .

$- x^{2} - 2 x + 8$

Factor $- 1$ out of $- x^{2}$ .

$- (x^{2}) - 2 x + 8$

Factor $- 1$ out of $- 2 x$ .

$- (x^{2}) - (2 x) + 8$

Rewrite $8$ as $- 1 (- 8)$ .

$- (x^{2}) - (2 x) - 1 (- 8)$

Factor $- 1$ out of $- (x^{2}) - (2 x)$ .

$- (x^{2} + 2 x) - 1 (- 8)$

Factor $- 1$ out of $- (x^{2} + 2 x) - 1 (- 8)$ .

$- (x^{2} + 2 x - 8)$

Step 2

Factor.

Factor $x^{2} + 2 x - 8$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 8$ and whose sum is $2$ .

$- 2, 4$

Write the factored form using these integers.

$- ((x - 2) (x + 4))$

Remove unnecessary parentheses.

$- (x - 2) (x + 4)$

Factor 8-2x-x^2

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