Factor 80x^2y-5y

$80 x^{2} y - 5 y$

Step 1

Factor $5 y$ out of $80 x^{2} y - 5 y$ .

Factor $5 y$ out of $80 x^{2} y$ .

$5 y (16 x^{2}) - 5 y$

Factor $5 y$ out of $- 5 y$ .

$5 y (16 x^{2}) + 5 y (- 1)$

Factor $5 y$ out of $5 y (16 x^{2}) + 5 y (- 1)$ .

$5 y (16 x^{2} - 1)$

Step 2

Rewrite $16 x^{2}$ as ${(4 x)}^{2}$ .

$5 y ({(4 x)}^{2} - 1)$

Step 3

Rewrite $1$ as $1^{2}$ .

$5 y ({(4 x)}^{2} - 1^{2})$

Step 4

Factor.

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 4 x$ and $b = 1$ .

$5 y ((4 x + 1) (4 x - 1))$

Remove unnecessary parentheses.

$5 y (4 x + 1) (4 x - 1)$