Factor 81-x^4

$81 - x^{4}$

Step 1

Rewrite $81$ as $9^{2}$ .

$9^{2} - x^{4}$

Step 2

Rewrite $x^{4}$ as ${(x^{2})}^{2}$ .

$9^{2} - {(x^{2})}^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 9$ and $b = x^{2}$ .

$(9 + x^{2}) (9 - x^{2})$

Step 4

Simplify.

Rewrite $9$ as $3^{2}$ .

$(9 + x^{2}) (3^{2} - x^{2})$

Factor.

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3$ and $b = x$ .

$(9 + x^{2}) ((3 + x) (3 - x))$

Remove unnecessary parentheses.

$(9 + x^{2}) (3 + x) (3 - x)$

Factor 81-x^4

Related Questions

Support LCMGCF.com by disabling your adblocker.