Factor 8x^2-28x-16

$8 x^{2} - 28 x - 16$

Step 1

Factor $4$ out of $8 x^{2} - 28 x - 16$ .

Factor $4$ out of $8 x^{2}$ .

$4 (2 x^{2}) - 28 x - 16$

Factor $4$ out of $- 28 x$ .

$4 (2 x^{2}) + 4 (- 7 x) - 16$

Factor $4$ out of $- 16$ .

$4 (2 x^{2}) + 4 (- 7 x) + 4 (- 4)$

Factor $4$ out of $4 (2 x^{2}) + 4 (- 7 x)$ .

$4 (2 x^{2} - 7 x) + 4 (- 4)$

Factor $4$ out of $4 (2 x^{2} - 7 x) + 4 (- 4)$ .

$4 (2 x^{2} - 7 x - 4)$

Step 2

Factor.

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 2 \cdot - 4 = - 8$ and whose sum is $b = - 7$ .

Factor $- 7$ out of $- 7 x$ .

$4 (2 x^{2} - 7 (x) - 4)$

Rewrite $- 7$ as $1$ plus $- 8$

$4 (2 x^{2} + (1 - 8) x - 4)$

Apply the distributive property.

$4 (2 x^{2} + 1 x - 8 x - 4)$

Multiply $x$ by $1$ .

$4 (2 x^{2} + x - 8 x - 4)$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$4 ((2 x^{2} + x) - 8 x - 4)$

Factor out the greatest common factor (GCF) from each group.

$4 (x (2 x + 1) - 4 (2 x + 1))$

Factor the polynomial by factoring out the greatest common factor, $2 x + 1$ .

$4 ((2 x + 1) (x - 4))$

Remove unnecessary parentheses.

$4 (2 x + 1) (x - 4)$

Factor 8x^2-28x-16

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