Factor 8x^2-9x+1

$8 x^{2} - 9 x + 1$

Step 1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 8 \cdot 1 = 8$ and whose sum is $b = - 9$ .

Factor $- 9$ out of $- 9 x$ .

$8 x^{2} - 9 (x) + 1$

Rewrite $- 9$ as $- 1$ plus $- 8$

$8 x^{2} + (- 1 - 8) x + 1$

Apply the distributive property.

$8 x^{2} - 1 x - 8 x + 1$

Step 2

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(8 x^{2} - 1 x) - 8 x + 1$

Factor out the greatest common factor (GCF) from each group.

$x (8 x - 1) - (8 x - 1)$

Step 3

Factor the polynomial by factoring out the greatest common factor, $8 x - 1$ .

$(8 x - 1) (x - 1)$

Factor 8x^2-9x+1

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