Factor 8x^3+125

$8 x^{3} + 125$

Step 1

Rewrite $8 x^{3}$ as ${(2 x)}^{3}$ .

${(2 x)}^{3} + 125$

Step 2

Rewrite $125$ as $5^{3}$ .

${(2 x)}^{3} + 5^{3}$

Step 3

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = 2 x$ and $b = 5$ .

$(2 x + 5) ({(2 x)}^{2} - (2 x) \cdot 5 + 5^{2})$

Step 4

Simplify.

Apply the product rule to $2 x$ .

$(2 x + 5) (2^{2} x^{2} - (2 x) \cdot 5 + 5^{2})$

Raise $2$ to the power of $2$ .

$(2 x + 5) (4 x^{2} - (2 x) \cdot 5 + 5^{2})$

Multiply $2$ by $- 1$ .

$(2 x + 5) (4 x^{2} - 2 x \cdot 5 + 5^{2})$

Multiply $5$ by $- 2$ .

$(2 x + 5) (4 x^{2} - 10 x + 5^{2})$

Raise $5$ to the power of $2$ .

$(2 x + 5) (4 x^{2} - 10 x + 25)$

Factor 8x^3+125

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