Factor 8x^3+64x^2-20x-160

$8 x^{3} + 64 x^{2} - 20 x - 160$

Step 1

Factor $4$ out of $8 x^{3} + 64 x^{2} - 20 x - 160$ .

Factor $4$ out of $8 x^{3}$ .

$4 (2 x^{3}) + 64 x^{2} - 20 x - 160$

Factor $4$ out of $64 x^{2}$ .

$4 (2 x^{3}) + 4 (16 x^{2}) - 20 x - 160$

Factor $4$ out of $- 20 x$ .

$4 (2 x^{3}) + 4 (16 x^{2}) + 4 (- 5 x) - 160$

Factor $4$ out of $- 160$ .

$4 (2 x^{3}) + 4 (16 x^{2}) + 4 (- 5 x) + 4 (- 40)$

Factor $4$ out of $4 (2 x^{3}) + 4 (16 x^{2})$ .

$4 (2 x^{3} + 16 x^{2}) + 4 (- 5 x) + 4 (- 40)$

Factor $4$ out of $4 (2 x^{3} + 16 x^{2}) + 4 (- 5 x)$ .

$4 (2 x^{3} + 16 x^{2} - 5 x) + 4 (- 40)$

Factor $4$ out of $4 (2 x^{3} + 16 x^{2} - 5 x) + 4 (- 40)$ .

$4 (2 x^{3} + 16 x^{2} - 5 x - 40)$

Step 2

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$4 ((2 x^{3} + 16 x^{2}) - 5 x - 40)$

Factor out the greatest common factor (GCF) from each group.

$4 (2 x^{2} (x + 8) - 5 (x + 8))$

Step 3

Factor.

Factor the polynomial by factoring out the greatest common factor, $x + 8$ .

$4 ((x + 8) (2 x^{2} - 5))$

Remove unnecessary parentheses.

$4 (x + 8) (2 x^{2} - 5)$