Factor 8x^3-8x

$8 x^{3} - 8 x$

Step 1

Factor $8 x$ out of $8 x^{3} - 8 x$ .

Factor $8 x$ out of $8 x^{3}$ .

$8 x (x^{2}) - 8 x$

Factor $8 x$ out of $- 8 x$ .

$8 x (x^{2}) + 8 x (- 1)$

Factor $8 x$ out of $8 x (x^{2}) + 8 x (- 1)$ .

$8 x (x^{2} - 1)$

Step 2

Rewrite $1$ as $1^{2}$ .

$8 x (x^{2} - 1^{2})$

Step 3

Factor.

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 1$ .

$8 x ((x + 1) (x - 1))$

Remove unnecessary parentheses.

$8 x (x + 1) (x - 1)$