Factor 8x^3+y^3

$8 x^{3} + y^{3}$

Step 1

Rewrite $8 x^{3}$ as ${(2 x)}^{3}$ .

${(2 x)}^{3} + y^{3}$

Step 2

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = 2 x$ and $b = y$ .

$(2 x + y) ({(2 x)}^{2} - (2 x) y + y^{2})$

Step 3

Simplify.

Apply the product rule to $2 x$ .

$(2 x + y) (2^{2} x^{2} - (2 x) y + y^{2})$

Raise $2$ to the power of $2$ .

$(2 x + y) (4 x^{2} - (2 x) y + y^{2})$

Multiply $2$ by $- 1$ .

$(2 x + y) (4 x^{2} - 2 x y + y^{2})$

Factor 8x^3+y^3

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