Factor 8x^5-25y^3+80x^4-x^2y^3+200x^3-10xy^3

$8 x^{5} - 25 y^{3} + 80 x^{4} - x^{2} y^{3} + 200 x^{3} - 10 x y^{3}$

Step 1

Regroup terms.

$8 x^{5} + 80 x^{4} + 200 x^{3} - 25 y^{3} - x^{2} y^{3} - 10 x y^{3}$

Step 2

Factor $8 x^{3}$ out of $8 x^{5} + 80 x^{4} + 200 x^{3}$ .

Factor $8 x^{3}$ out of $8 x^{5}$ .

$8 x^{3} (x^{2}) + 80 x^{4} + 200 x^{3} - 25 y^{3} - x^{2} y^{3} - 10 x y^{3}$

Factor $8 x^{3}$ out of $80 x^{4}$ .

$8 x^{3} (x^{2}) + 8 x^{3} (10 x) + 200 x^{3} - 25 y^{3} - x^{2} y^{3} - 10 x y^{3}$

Factor $8 x^{3}$ out of $200 x^{3}$ .

$8 x^{3} (x^{2}) + 8 x^{3} (10 x) + 8 x^{3} (25) - 25 y^{3} - x^{2} y^{3} - 10 x y^{3}$

Factor $8 x^{3}$ out of $8 x^{3} (x^{2}) + 8 x^{3} (10 x)$ .

$8 x^{3} (x^{2} + 10 x) + 8 x^{3} (25) - 25 y^{3} - x^{2} y^{3} - 10 x y^{3}$

Factor $8 x^{3}$ out of $8 x^{3} (x^{2} + 10 x) + 8 x^{3} (25)$ .

$8 x^{3} (x^{2} + 10 x + 25) - 25 y^{3} - x^{2} y^{3} - 10 x y^{3}$

Step 3

Factor using the perfect square rule.

Rewrite $25$ as $5^{2}$ .

$8 x^{3} (x^{2} + 10 x + 5^{2}) - 25 y^{3} - x^{2} y^{3} - 10 x y^{3}$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$10 x = 2 \cdot x \cdot 5$

Rewrite the polynomial.

$8 x^{3} (x^{2} + 2 \cdot x \cdot 5 + 5^{2}) - 25 y^{3} - x^{2} y^{3} - 10 x y^{3}$

Factor using the perfect square trinomial rule $a^{2} + 2 a b + b^{2} = {(a + b)}^{2}$ , where $a = x$ and $b = 5$ .

$8 x^{3} {(x + 5)}^{2} - 25 y^{3} - x^{2} y^{3} - 10 x y^{3}$

Step 4

Factor $y^{3}$ out of $- 25 y^{3} - x^{2} y^{3} - 10 x y^{3}$ .

Factor $y^{3}$ out of $- 25 y^{3}$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} \cdot - 25 - x^{2} y^{3} - 10 x y^{3}$

Factor $y^{3}$ out of $- x^{2} y^{3}$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} \cdot - 25 + y^{3} (- x^{2}) - 10 x y^{3}$

Factor $y^{3}$ out of $- 10 x y^{3}$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} \cdot - 25 + y^{3} (- x^{2}) + y^{3} (- 10 x)$

Factor $y^{3}$ out of $y^{3} \cdot - 25 + y^{3} (- x^{2})$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} \cdot (- 25 - x^{2}) + y^{3} (- 10 x)$

Factor $y^{3}$ out of $y^{3} \cdot (- 25 - x^{2}) + y^{3} (- 10 x)$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} (- 25 - x^{2} - 10 x)$

Step 5

Factor.

Factor by grouping.

Reorder terms.

$8 x^{3} {(x + 5)}^{2} + y^{3} (- x^{2} - 10 x - 25)$

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = - 1 \cdot - 25 = 25$ and whose sum is $b = - 10$ .

Factor $- 10$ out of $- 10 x$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} (- x^{2} - 10 (x) - 25)$

Rewrite $- 10$ as $- 5$ plus $- 5$

$8 x^{3} {(x + 5)}^{2} + y^{3} (- x^{2} + (- 5 - 5) x - 25)$

Apply the distributive property.

$8 x^{3} {(x + 5)}^{2} + y^{3} (- x^{2} - 5 x - 5 x - 25)$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$8 x^{3} {(x + 5)}^{2} + y^{3} ((- x^{2} - 5 x) - 5 x - 25)$

Factor out the greatest common factor (GCF) from each group.

$8 x^{3} {(x + 5)}^{2} + y^{3} (x (- x - 5) + 5 (- x - 5))$

Factor the polynomial by factoring out the greatest common factor, $- x - 5$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} ((- x - 5) (x + 5))$

Remove unnecessary parentheses.

$8 x^{3} {(x + 5)}^{2} + y^{3} (- x - 5) (x + 5)$

Step 6

Combine exponents.

Factor $- 1$ out of $- x$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} (- (x) - 5) (x + 5)$

Rewrite $- 5$ as $- 1 (5)$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} (- (x) - 1 (5)) (x + 5)$

Factor $- 1$ out of $- (x) - 1 (5)$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} (- (x + 5)) (x + 5)$

Rewrite $- (x + 5)$ as $- 1 (x + 5)$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} (- 1 (x + 5)) (x + 5)$

Remove parentheses.

$8 x^{3} {(x + 5)}^{2} + y^{3} \cdot - 1 (x + 5) (x + 5)$

Raise $x + 5$ to the power of $1$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} \cdot - 1 ({(x + 5)}^{1} (x + 5))$

Raise $x + 5$ to the power of $1$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} \cdot - 1 ({(x + 5)}^{1} {(x + 5)}^{1})$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$8 x^{3} {(x + 5)}^{2} + y^{3} \cdot - 1 {(x + 5)}^{1 + 1}$

Add $1$ and $1$ .

$8 x^{3} {(x + 5)}^{2} + y^{3} \cdot - 1 {(x + 5)}^{2}$

Step 7

Factor ${(x + 5)}^{2}$ out of $8 x^{3} {(x + 5)}^{2} + y^{3} \cdot - 1 {(x + 5)}^{2}$ .

Factor ${(x + 5)}^{2}$ out of $8 x^{3} {(x + 5)}^{2}$ .

${(x + 5)}^{2} (8 x^{3}) + y^{3} \cdot - 1 {(x + 5)}^{2}$

Factor ${(x + 5)}^{2}$ out of $y^{3} \cdot - 1 {(x + 5)}^{2}$ .

${(x + 5)}^{2} (8 x^{3}) + {(x + 5)}^{2} (y^{3} \cdot - 1)$

Factor ${(x + 5)}^{2}$ out of ${(x + 5)}^{2} (8 x^{3}) + {(x + 5)}^{2} (y^{3} \cdot - 1)$ .

${(x + 5)}^{2} (8 x^{3} + y^{3} \cdot - 1)$

Step 8

Rewrite $8 x^{3}$ as ${(2 x)}^{3}$ .

${(x + 5)}^{2} ({(2 x)}^{3} + y^{3} \cdot - 1)$

Step 9

Rewrite $y^{3} \cdot - 1$ as ${(y \cdot - 1)}^{3}$ .

${(x + 5)}^{2} ({(2 x)}^{3} + {(y \cdot - 1)}^{3})$

Step 10

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = 2 x$ and $b = y \cdot - 1$ .

${(x + 5)}^{2} ((2 x + y \cdot - 1) ({(2 x)}^{2} - (2 x) (y \cdot - 1) + {(y \cdot - 1)}^{2}))$

Step 11

Factor.

Simplify.

Move $- 1$ to the left of $y$ .

${(x + 5)}^{2} ((2 x - 1 y) ({(2 x)}^{2} - (2 x) (y \cdot - 1) + {(y \cdot - 1)}^{2}))$

Rewrite $- 1 y$ as $- y$ .

${(x + 5)}^{2} ((2 x - y) ({(2 x)}^{2} - (2 x) (y \cdot - 1) + {(y \cdot - 1)}^{2}))$

Apply the product rule to $2 x$ .

${(x + 5)}^{2} ((2 x - y) (2^{2} x^{2} - (2 x) (y \cdot - 1) + {(y \cdot - 1)}^{2}))$

Raise $2$ to the power of $2$ .

${(x + 5)}^{2} ((2 x - y) (4 x^{2} - (2 x) (y \cdot - 1) + {(y \cdot - 1)}^{2}))$

Multiply $2$ by $- 1$ .

${(x + 5)}^{2} ((2 x - y) (4 x^{2} - 2 x (y \cdot - 1) + {(y \cdot - 1)}^{2}))$

Move $- 1$ to the left of $y$ .

${(x + 5)}^{2} ((2 x - y) (4 x^{2} - 2 x (- 1 \cdot y) + {(y \cdot - 1)}^{2}))$

Rewrite using the commutative property of multiplication.

${(x + 5)}^{2} ((2 x - y) (4 x^{2} - 2 \cdot - 1 x y + {(y \cdot - 1)}^{2}))$

Multiply $- 2$ by $- 1$ .

${(x + 5)}^{2} ((2 x - y) (4 x^{2} + 2 x y + {(y \cdot - 1)}^{2}))$

Move $- 1$ to the left of $y$ .

${(x + 5)}^{2} ((2 x - y) (4 x^{2} + 2 x y + {(- 1 y)}^{2}))$

Rewrite $- 1 y$ as $- y$ .

${(x + 5)}^{2} ((2 x - y) (4 x^{2} + 2 x y + {(- y)}^{2}))$

Apply the product rule to $- y$ .

${(x + 5)}^{2} ((2 x - y) (4 x^{2} + 2 x y + {(- 1)}^{2} y^{2}))$

Raise $- 1$ to the power of $2$ .

${(x + 5)}^{2} ((2 x - y) (4 x^{2} + 2 x y + 1 y^{2}))$

Multiply $y^{2}$ by $1$ .

${(x + 5)}^{2} ((2 x - y) (4 x^{2} + 2 x y + y^{2}))$

Remove unnecessary parentheses.

${(x + 5)}^{2} (2 x - y) (4 x^{2} + 2 x y + y^{2})$

Factor 8x^5-25y^3+80x^4-x^2y^3+200x^3-10xy^3

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