Factor 9-64x^2

$9 - 64 x^{2}$

Step 1

Rewrite $9$ as $3^{2}$ .

$3^{2} - 64 x^{2}$

Step 2

Rewrite $64 x^{2}$ as ${(8 x)}^{2}$ .

$3^{2} - {(8 x)}^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3$ and $b = 8 x$ .

$(3 + 8 x) (3 - (8 x))$

Step 4

Multiply $8$ by $- 1$ .

$(3 + 8 x) (3 - 8 x)$