Factor (9(t-4)^8(5t+8)^9-9(5t+8)^8*5(t-4)^9)/(((5t+8)^9)^2)

$\frac{9 {(t - 4)}^{8} {(5 t + 8)}^{9} - 9 {(5 t + 8)}^{8} \cdot 5 {(t - 4)}^{9}}{{({(5 t + 8)}^{9})}^{2}}$

Step 1

Factor $9 {(t - 4)}^{8} {(5 t + 8)}^{8}$ out of $9 {(t - 4)}^{8} {(5 t + 8)}^{9} - 9 {(5 t + 8)}^{8} \cdot (5 {(t - 4)}^{9})$ .

Factor $9 {(t - 4)}^{8} {(5 t + 8)}^{8}$ out of $9 {(t - 4)}^{8} {(5 t + 8)}^{9}$ .

$\frac{9 {(t - 4)}^{8} {(5 t + 8)}^{8} (5 t + 8) - 9 {(5 t + 8)}^{8} \cdot (5 {(t - 4)}^{9})}{{({(5 t + 8)}^{9})}^{2}}$

Factor $9 {(t - 4)}^{8} {(5 t + 8)}^{8}$ out of $- 9 {(5 t + 8)}^{8} \cdot (5 {(t - 4)}^{9})$ .

$\frac{9 {(t - 4)}^{8} {(5 t + 8)}^{8} (5 t + 8) + 9 {(t - 4)}^{8} {(5 t + 8)}^{8} (- 1 \cdot (5 (t - 4)))}{{({(5 t + 8)}^{9})}^{2}}$

Factor $9 {(t - 4)}^{8} {(5 t + 8)}^{8}$ out of $9 {(t - 4)}^{8} {(5 t + 8)}^{8} (5 t + 8) + 9 {(t - 4)}^{8} {(5 t + 8)}^{8} (- 1 \cdot (5 (t - 4)))$ .

$\frac{9 {(t - 4)}^{8} {(5 t + 8)}^{8} (5 t + 8 - 1 \cdot (5 (t - 4)))}{{({(5 t + 8)}^{9})}^{2}}$

Step 2

Multiply $5$ by $- 1$ .

$\frac{9 {(t - 4)}^{8} {(5 t + 8)}^{8} (5 t + 8 - 5 (t - 4))}{{({(5 t + 8)}^{9})}^{2}}$

Step 3

Apply the distributive property.

$\frac{9 {(t - 4)}^{8} {(5 t + 8)}^{8} (5 t + 8 - 5 t - 5 \cdot - 4)}{{({(5 t + 8)}^{9})}^{2}}$

Step 4

Multiply $- 5$ by $- 4$ .

$\frac{9 {(t - 4)}^{8} {(5 t + 8)}^{8} (5 t + 8 - 5 t + 20)}{{({(5 t + 8)}^{9})}^{2}}$

Step 5

Subtract $5 t$ from $5 t$ .

$\frac{9 {(t - 4)}^{8} {(5 t + 8)}^{8} (0 + 8 + 20)}{{({(5 t + 8)}^{9})}^{2}}$

Step 6

Add $0$ and $8$ .

$\frac{9 {(t - 4)}^{8} {(5 t + 8)}^{8} (8 + 20)}{{({(5 t + 8)}^{9})}^{2}}$

Step 7

Add $8$ and $20$ .

$\frac{9 {(t - 4)}^{8} {(5 t + 8)}^{8} \cdot 28}{{({(5 t + 8)}^{9})}^{2}}$

Step 8

Multiply $28$ by $9$ .

$\frac{252 {(t - 4)}^{8} {(5 t + 8)}^{8}}{{({(5 t + 8)}^{9})}^{2}}$

Factor (9(t-4)^8(5t+8)^9-9(5t+8)^8*5(t-4)^9)/(((5t+8)^9)^2)

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