Factor 9a^2+6a-8

$9 a^{2} + 6 a - 8$

Step 1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 9 \cdot - 8 = - 72$ and whose sum is $b = 6$ .

Factor $6$ out of $6 a$ .

$9 a^{2} + 6 (a) - 8$

Rewrite $6$ as $- 6$ plus $12$

$9 a^{2} + (- 6 + 12) a - 8$

Apply the distributive property.

$9 a^{2} - 6 a + 12 a - 8$

Step 2

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(9 a^{2} - 6 a) + 12 a - 8$

Factor out the greatest common factor (GCF) from each group.

$3 a (3 a - 2) + 4 (3 a - 2)$

Step 3

Factor the polynomial by factoring out the greatest common factor, $3 a - 2$ .

$(3 a - 2) (3 a + 4)$

Factor 9a^2+6a-8

Related Questions

Support LCMGCF.com by disabling your adblocker.