Factor 9a^4-b^2

$9 a^{4} - b^{2}$

Step 1

Rewrite $9 a^{4}$ as ${(3 a^{2})}^{2}$ .

${(3 a^{2})}^{2} - b^{2}$

Step 2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3 a^{2}$ and $b = b$ .

$(3 a^{2} + b) (3 a^{2} - b)$

Factor 9a^4-b^2

Related Questions

Support LCMGCF.com by disabling your adblocker.