Factor 9m^2-4/9

$9 m^{2} - \frac{4}{9}$

Step 1

Rewrite $9 m^{2}$ as ${(3 m)}^{2}$ .

${(3 m)}^{2} - \frac{4}{9}$

Step 2

Rewrite $\frac{4}{9}$ as ${(\frac{2}{3})}^{2}$ .

${(3 m)}^{2} - {(\frac{2}{3})}^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3 m$ and $b = \frac{2}{3}$ .

$(3 m + \frac{2}{3}) (3 m - \frac{2}{3})$

Factor 9m^2-4/9

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