Factor 9n^2-4

$9 n^{2} - 4$

Step 1

Rewrite $9 n^{2}$ as ${(3 n)}^{2}$ .

${(3 n)}^{2} - 4$

Step 2

Rewrite $4$ as $2^{2}$ .

${(3 n)}^{2} - 2^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3 n$ and $b = 2$ .

$(3 n + 2) (3 n - 2)$