Factor 9u^2-9u+2

$9 u^{2} - 9 u + 2$

Step 1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 9 \cdot 2 = 18$ and whose sum is $b = - 9$ .

Factor $- 9$ out of $- 9 u$ .

$9 u^{2} - 9 (u) + 2$

Rewrite $- 9$ as $- 3$ plus $- 6$

$9 u^{2} + (- 3 - 6) u + 2$

Apply the distributive property.

$9 u^{2} - 3 u - 6 u + 2$

Step 2

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(9 u^{2} - 3 u) - 6 u + 2$

Factor out the greatest common factor (GCF) from each group.

$3 u (3 u - 1) - 2 (3 u - 1)$

Step 3

Factor the polynomial by factoring out the greatest common factor, $3 u - 1$ .

$(3 u - 1) (3 u - 2)$

Factor 9u^2-9u+2

Related Questions

Support LCMGCF.com by disabling your adblocker.