Factor 9x^2+21x-8=0

$9 x^{2} + 21 x - 8 = 0$

Step 1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 9 \cdot - 8 = - 72$ and whose sum is $b = 21$ .

Factor $21$ out of $21 x$ .

$9 x^{2} + 21 (x) - 8 = 0$

Rewrite $21$ as $- 3$ plus $24$

$9 x^{2} + (- 3 + 24) x - 8 = 0$

Apply the distributive property.

$9 x^{2} - 3 x + 24 x - 8 = 0$

Step 2

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(9 x^{2} - 3 x) + 24 x - 8 = 0$

Factor out the greatest common factor (GCF) from each group.

$3 x (3 x - 1) + 8 (3 x - 1) = 0$

Step 3

Factor the polynomial by factoring out the greatest common factor, $3 x - 1$ .

$(3 x - 1) (3 x + 8) = 0$

Factor 9x^2+21x-8=0

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