Factor 9x^2-4x-5

$9 x^{2} - 4 x - 5$

Step 1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 9 \cdot - 5 = - 45$ and whose sum is $b = - 4$ .

Factor $- 4$ out of $- 4 x$ .

$9 x^{2} - 4 (x) - 5$

Rewrite $- 4$ as $5$ plus $- 9$

$9 x^{2} + (5 - 9) x - 5$

Apply the distributive property.

$9 x^{2} + 5 x - 9 x - 5$

Step 2

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(9 x^{2} + 5 x) - 9 x - 5$

Factor out the greatest common factor (GCF) from each group.

$x (9 x + 5) - (9 x + 5)$

Step 3

Factor the polynomial by factoring out the greatest common factor, $9 x + 5$ .

$(9 x + 5) (x - 1)$

Factor 9x^2-4x-5

Related Questions

Support LCMGCF.com by disabling your adblocker.