Factor 9x^2-4y^2

$9 x^{2} - 4 y^{2}$

Step 1

Rewrite $9 x^{2}$ as ${(3 x)}^{2}$ .

${(3 x)}^{2} - 4 y^{2}$

Step 2

Rewrite $4 y^{2}$ as ${(2 y)}^{2}$ .

${(3 x)}^{2} - {(2 y)}^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3 x$ and $b = 2 y$ .

$(3 x + 2 y) (3 x - (2 y))$

Step 4

Multiply $2$ by $- 1$ .

$(3 x + 2 y) (3 x - 2 y)$

Factor 9x^2-4y^2

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