Factor 9x^4-y^2

$9 x^{4} - y^{2}$

Rewrite $9 x^{4}$ as ${(3 x^{2})}^{2}$ .

${(3 x^{2})}^{2} - y^{2}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3 x^{2}$ and $b = y$ .

$(3 x^{2} + y) (3 x^{2} - y)$

Factor 9x^4-y^2

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