Factor 9x^4y^2-z^6

$9 x^{4} y^{2} - z^{6}$

Step 1

Rewrite $9 x^{4} y^{2}$ as ${(3 x^{2} y)}^{2}$ .

${(3 x^{2} y)}^{2} - z^{6}$

Step 2

Rewrite $z^{6}$ as ${(z^{3})}^{2}$ .

${(3 x^{2} y)}^{2} - {(z^{3})}^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3 x^{2} y$ and $b = z^{3}$ .

$(3 x^{2} y + z^{3}) (3 x^{2} y - z^{3})$

Factor 9x^4y^2-z^6

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