Factor 9x^6-y^8

$9 x^{6} - y^{8}$

Step 1

Rewrite $9 x^{6}$ as ${(3 x^{3})}^{2}$ .

${(3 x^{3})}^{2} - y^{8}$

Step 2

Rewrite $y^{8}$ as ${(y^{4})}^{2}$ .

${(3 x^{3})}^{2} - {(y^{4})}^{2}$

Step 3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3 x^{3}$ and $b = y^{4}$ .

$(3 x^{3} + y^{4}) (3 x^{3} - y^{4})$

Factor 9x^6-y^8

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